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Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1
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have you any method to use for this question...?
not really no
so what methods do you know.. 1. find the focal length and then find the vertex... 2. use the distance formula..
number 1
ok.... so start by plotting the given information |dw:1437680444218:dw| so this tells me the parabola is concave up... does that make sense...
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yes
ok... so the line of symmetry is x = -5 and the vertex is a units below the focus... where a = the focal length so |dw:1437680607256:dw|
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