Question

Solve the following system of equations by substitution:

4x − 6y = 28
8x − 4y = 24

x = 1, y = 4
x = −1, y = 4
x = 1, y = −4
x = −1, y = −4

Answer 1

Multiply first equation by 2, 8x-12y=56
8x-12y=56
8x − 4y = 24

Subtract X, -8y=32,
y = -4

plug in y into any of 2 equations

Answer 2

4x-6(-4)=28, 4x+24=28, 4x=4, x = 1, {1,-4) = C

Answer 3

Now I get it! Thank you so much!!!

Answer 4

Your welcome :)