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logarithm question
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\(\large \color{black}{\begin{align} & 5^{x}=10\ \normalsize \text{then}\ x \ \text{ is equal to}\hspace{.33em}\\~\\ & a.)\ \log 5 \hspace{.33em}\\~\\ & b.)\ \dfrac{\log 10}{\log 2} \hspace{.33em}\\~\\ & c.)\ \log 2 \hspace{.33em}\\~\\ & d.)\ \dfrac{1}{\log 5} \hspace{.33em}\\~\\ \end{align}}\)
You first log both sides.
log 5^x=log 10
\(\large \color{black}{\begin{align} x=\dfrac{\log 10}{\log 5} \hspace{.33em}\\~\\ \end{align}}\)
lol i forgot log 10=1 silly me
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thanks the answer x=log10/log5
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