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If h(x) = 6 – x, what is the value of (h*h)(10)
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Hint : (h*h)(10) = h(10) * h(10)
6-x(10) * 6-x(10)??
ah this isn't composite functions.. ok I got confused for a second since we have h(x) = 6-x and (h(x))(h(x)) we just multiply (6-x)(6-x) and then evaluate the result when x = 10
yay 16
or we could obtain the result a bit faster if we let x = 10 immediately and have (6-10)(6-10) oh cool you got it! :D
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(-4)(-4) = 16
thank you!
\[36-6x-6x+x^2 \rightarrow 36-12x+x^2 \] at x = 10 \[36-12(10)+(10)^2 = 36-120+100=16 \] yay!
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