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Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0
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"(sin x)(cos x) " you can make this a double angle in sin or you can just go through and work out when either sinx= or cos x = 0, because the other is always -1 < < 1 do you have a preference?
I actually have a clue with this, but I just want to make sure I was correct. I made sin x=0 and cos x=0, so my answers are 0, pi/2,pi, 3pi/2
what about \(2 \pi\)?
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