Question

Find the area of the region between y=e^X; y=x^(2)+1;x=-1;x=1

Answer 1

maybe y=x²-1 ?
because with y=x²+1 u get two different regions

Answer 2

from -1<x<0 , x^2+1 > e^x
\[Area = \int\limits_{-1}^0 (x^2 +1) - e^x\]

from 0<x<1, e^x > x^2+1
\[Area = \int\limits_0^1 e^x - (x^2 +1)\]