Question

Find the area of the region between y=(x-2)^2,y=x. The answer is 9/2. I got 6 though.

Answer 1

did it again and got 7/2

Answer 2

Now I got -9/2 I must have forgotten a negative somewhere or the book is wrong.

Answer 3

area between: \(y=(x-2)^2\) and \(y=x\)

\(\large \int_{1}^{4} x - (x-2)^2 \ dx\)

it is 9/2

Answer 4

wait isn't (x-2)^2 greater than x?