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Find the zeros of the function. f(x) = x2 - 6x + 8 -4 and 2 4 and 2 -4 and -2 4 and -2
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\[0 = x^2 - 6x +8\]
when y=f(x) = 0 , the function will cross the x-axis
can you factor that, or use quadratic form
the answers are whole numbers, so it will go into 0 = (x + ) *(x - )
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