Challenge! Ready? Find the magnitude and direction of the vector. Round the length to the nearest tenth and the degree to the nearest unit. Diagram is not drawn to scale.

Question

anonymous · Answer

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anonymous · Answer

Find the magnitude and direction of the vector
You could find the magnitude using pythagoras, or by using trig.

The question asks for direction, which probably should be in the form  NxxºE
(North and so many degrees to the East). the magnitude is sin(A)= 6/M  or M= 6/sin(A)= 6/sin(56.3)= 7.2 ft
(If we use pythagoras:  sqrt( 4^2 + 6^2) = sqrt(52)= 7.2 ft  (Good!)
answer:
7.2 ft in the direction N56.3ºE. They want the degree to the nearest unit, and the magnitude to the nearest tenth, so the real answer is
7.2 ft in the direction N56ºE. Is that right?