Question

help please, check the attachment, thank you!!

Answer 1

x = 2 plug in the answers and 2 works

Answer 2

@samanthaavera thank you!!

Answer 3

Yes. that's correct.when x = 2
\[\LARGE \frac{2}{3}x+\frac{8}{3} =2^x\]
\[\LARGE \frac{2}{3}(2)+\frac{8}{3} =2^2\]
\[\LARGE \frac{4}{3}+\frac{8}{3} =4\]
\[\LARGE \frac{12}{3} =4\]
\[\LARGE 4 =4\]

Answer 4

@UsukiDoll i appreciate you double checking, thanks a lot!!