The new business building uptown is building a wall made entirely of glass pyramids. Each pyramid will have a square base with length of 8 inches and height of 10 inches. If the wall requires 250 of these pyramids, what volume of glass will be used? Round to the nearest cubic inch.
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OpenStudy (anonymous):
If a pyramid has a base of B square units, and a height of h units, then the
a Pyramid volume V is 1/3 B x h cubic units, or V = 1/3 Bh ... the Base has to be AREA so with a square base you would need to square the side length to be in squared form
for this it needs to be V=1/3(8)^2 X (10)
= 1/3(64)(10) ............ = 21.12 x 10 = ..........211cm^3
OpenStudy (anonymous):
v=a^2*h/3
so v=8^2*10/3
OpenStudy (anonymous):
do 10/3 first @Aliypop
OpenStudy (anonymous):
3.33333333
OpenStudy (anonymous):
yep now do 8*8
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OpenStudy (anonymous):
64
OpenStudy (anonymous):
now do 64*3.333333333333333333333333333333333333333
OpenStudy (anonymous):
213.333333
OpenStudy (anonymous):
yep do 213.333333*250
OpenStudy (anonymous):
53,333.33325
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