Question

@purplemexican

Answer 1

\[\frac{ x^2 + 27 }{ x+8 }= \frac{ 3x+67 }{ x+8 }\]

Answer 2

When you go to solve this, you have to keep track from the start that...
\[(x + 8) \ne 0 ~~or~~x \ne -8\]

may or may not be extraneous