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f(x)=1/x and g(x)=x^2-4x what two numbers are not in the domainof f o g?
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@welshfella
f o g = 1/ (x^2 - 4x)
thx bro @welshfella
= 1 / (x(x - 4))
do i have to simplify that at all?
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no what you need to do now is to work out what 2 values of x will make the denominator = zero. These 2 numbers will not be in the domain of f o g
(0,4)
basically you need to solve x(x - 4) = 0 yea you got it
good gtg
ok ttyl
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