Question

@ganeshie8

Answer 1

think my teacher might be wrong on something, need to check here.

https://www.desmos.com/calculator/mdavtmnba2

for that graph, find the area inside the rose, but outside the circle.

Answer 2

teachers solutions say just integrate (4cos(2theta))^2-2^2 from 0 to pi/6 then use symmetry.

Answer 3

teacher used this equation here http://tutorial.math.lamar.edu/Classes/CalcII/PolarArea_files/eq0008MP.gif but im not sure if u can do that in this case?