Question

Help me if possible!!
Solve for x: 25x2 - 36 = 0 (2 points)

x = 6, 5

x = -6, -5

x = , x = -

x = , x = -

Answer 1

What are the last 2 choices?

Answer 2

for c it is 36 over 25 and negative 36 over 25 (as in the whole equation.
for d it is 6 over 5 and negative 6 over 5 (whole equation is neg)

Answer 3

sorry it idnt come through

Answer 4

Add 36 to both sides.
\[\huge~\rm~25x^2−36+36=0+36\]\[\huge~\rm~25x^2=36\]

Answer 5

Do you know what to do from here?

Answer 6

do i divide??

Answer 7

wait no

Answer 8

yes! :D
I added 36 to both sides because we are trying to ISOLATE x :)
Next step is indeed to divide!

Answer 9

oksy

Answer 10

is the answer d?

Answer 11

Thats correct

Answer 12

thank you so much.

Answer 13

You simplyfy the orginal answer which is
36/25

Answer 14

No problem :)

Answer 15

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Answer 16

\[25x^2 - 36 = 0\\(5x)^2-6^2=0\\(5x+6)(5x-6)=0\ [use\ a^2-b^2=(a+b+(a-b)]\\ \implies\ either\ (5x+6)=0\ or\ (5x-6)=0\\ \implies\ either\ 5x=-6\ or\ 5x=6\\ \implies\ either\ x=\frac{ -6 }{ 5 }\ or\ x=\frac{ 6 }{5 }\]