Question

Check my answer. Rewrite with only sin x and cos x.

sin 2x - cos x.

Answer 1

\[2 sinx cosx -cosx\]
\[\cos x(2sinx-1)\]

correct?

Answer 2

Choices:
A. 2 sin x cos2x
B. sin x
C. cos x (2 sin x - 1)
D. 2 sin x

Answer 3

yes right
sin(2x)=2sin(x)cos(x)

2sin(x)cos(x)-cos(x)
both terms have common factor cos(x)
cos(x)[2sin(x)-1]