How many solutions does this linear system have?

y = 2x – 5

–8x – 4y = –20

Question

How many solutions does this linear system have?

y = 2x – 5      

–8x – 4y = –20

anonymous · Answer

A. one solution: (–2.5, 0)

B. one solution: (2.5, 0)

C. no solution

D. infinite number of solutions

mrnood · Answer

the first equation tells you that you can write y in terms of x (i.e wherever there is y it is the SAME as 2x-5)

SO

In the second equation you can substitute (2x-5) WHEREVER there is y

that will allow oyu to find a solution for x....

lynfran · Answer

y=2x-5
y=(-20+8x)/-4
$$2x-5=-\frac{ 8x-20 }{ 4 }$$$$8x-20=-8x+20$$$$8x+8x=20+20$$

lynfran · Answer

what did u  get when u solve for x??