Question

CaCO3---> CaO+CO2
How many moles of CaO form when 98.60g CaCO3 decompose?
98.60g CaCO3= ______ mol CaO

Answer 1

Hey I think it is going to be 0986 moles. Cuz we can see that no. of moles of CaCO3 which will decompose is equivalent to the no. of CaO . Now it's just the matter of finding the no. of moles of CaCO3 . \[no. of moles = \frac{ mass }{ relative molecular mass }\]