Question

MEDAL
In the expansion of (3a + 4b)^8, which of the following are possible variable terms? Explain your reasoning. a^2b^3; a^5b^3; ab^8; b^8; a^4b^4; a^8; ab^7; a^6b^5

Answer 1

Use binomial expansion to solve it.

Answer 2

a^4b^4, a^8, and b^8 because they add up to 8.

Answer 3

Gimme a few mins to do it for ya

Answer 4

\[(3a+4b)^8= 6561 a^8+69984 a^7 b+326592 a^6 b^2+870912 a^5 b^3+1451520 a^4 b^4+1548288 a^3 b^5+1032192 a^2 b^6+393216 a b^7+65536 b^8\]

Answer 5

So theres \[a^8 +a^7b+a^6b^2+a^5b^3+a^4b^4+a^3b^5+a^2b^6+ab^7+b^8\]

Answer 6

Ya need help with the reasoning part?