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Mathematics 10 Online
OpenStudy (anonymous):

Check my work?

OpenStudy (anonymous):

I need to find the vertex of f(x) = 5x2 + 2x + 1

OpenStudy (anonymous):

f(x) = 5x2 + 2x + 1 a = 5; b = 2; c = 1 x = (-2)/10 = (-1)/5 f(x) = 5((-1)/5)2 + 2((-1)/5) + 1 f(x) = -1 + (-0.4) +1 x = (-1)/5; y = -0.4

OpenStudy (anonymous):

@Elsa213 @Empty @EmilyD22 @freckles @pooja195 @skullpatrol

OpenStudy (anonymous):

@Loser66

OpenStudy (anonymous):

So, am I right @Loser66 ?

OpenStudy (loser66):

y = 4/5

OpenStudy (anonymous):

Hmmm, can you walk me through on how?

OpenStudy (anonymous):

Oh, I see, change the decimal to a fraction.

OpenStudy (anonymous):

Wait, no.

OpenStudy (loser66):

\(y=5(\dfrac{-1}{5})^2 +2*\dfrac{-1}{5}+1 =5*\dfrac{1}{25}-\dfrac{2}{5}+1\) \(=\dfrac{1}{5} -\dfrac{2}{5}+1=-\dfrac{1}{5}+1=\dfrac{-1}{5}+\dfrac{5}{5}=\dfrac{4}{5}\)

OpenStudy (anonymous):

Ok, was x right?

OpenStudy (loser66):

yes

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