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I need to find the vertex of f(x) = 5x2 + 2x + 1
f(x) = 5x2 + 2x + 1 a = 5; b = 2; c = 1 x = (-2)/10 = (-1)/5 f(x) = 5((-1)/5)2 + 2((-1)/5) + 1 f(x) = -1 + (-0.4) +1 x = (-1)/5; y = -0.4
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@Loser66
So, am I right @Loser66 ?
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y = 4/5
Hmmm, can you walk me through on how?
Oh, I see, change the decimal to a fraction.
Wait, no.
\(y=5(\dfrac{-1}{5})^2 +2*\dfrac{-1}{5}+1 =5*\dfrac{1}{25}-\dfrac{2}{5}+1\) \(=\dfrac{1}{5} -\dfrac{2}{5}+1=-\dfrac{1}{5}+1=\dfrac{-1}{5}+\dfrac{5}{5}=\dfrac{4}{5}\)
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Ok, was x right?
yes
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