Two metal balls have charges of 7.1 * 10ÈÒ coulombs and
6.9 * 10ÈÒ coulombs. They are 5.7 * 10È¹ meters apart. What is the force of interaction between the two balls?
(k = 9.0 * 10© newton·metersÆ/coulombÆ)
A. 5.7 newtons
B. 6.9 newtons
C. 7.1 newtons
D. 1.4 newtons

Question

Two metal balls have charges of 7.1 * 10ÈÒ coulombs and
6.9 * 10ÈÒ coulombs. They are 5.7 * 10È¹ meters apart. What is the force of interaction between the two balls?
(k = 9.0 * 10© newton·metersÆ/coulombÆ)
A. 5.7 newtons
B. 6.9 newtons
C. 7.1 newtons
D. 1.4 newtons

anonymous · Answer

help me with this one please!? @rvc

michele_laino · Answer

hint:
the magnitude of the requested force, is given by  the Coulomb's law:
$$\Large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}}$$ 
where Q1, Q2 are the electric charges, d is the distance between the metal balls