The force of repulsion between two like-charged table tennis balls is 8.2 * 10È¥ newtons. If the charge on the two objects is
6.7 * 10È© coulombs each, what is the distance between the two charges? (k = 9.0 * 10© newton·metersÆ/coulombÆ)
a: 0.23
b: 0.70
c:6.7
d:8.2

Question

The force of repulsion between two like-charged table tennis balls is 8.2 * 10È¥ newtons. If the charge on the two objects is
6.7 * 10È© coulombs each, what is the distance between the two charges? (k = 9.0 * 10© newton·metersÆ/coulombÆ) 
a: 0.23
b: 0.70
c:6.7
d:8.2

irishboy123 · Answer

Coulomb's Law:


$\large F = k \frac{q_1 \ q_2 }{r^2}$

$q_1 = q_2$