Question

Use implicit differentiation to find slope of tangent line to the curve xy-y^2+4x=-2 at the point (1,-2)

Answer 1

\(xy-y^2+4x=-2\)
so:
\(\frac{d}{dx}(xy)-\frac{d}{dx}(y^2)+\frac{d}{dx}(4x)=\frac{d}{dx}(-2)\)

what do you get?