Question

http://i.imgur.com/3dAFKoJ.png since it looks like an equilateral triangle but it's not so I have no idea sure if I should use sin or cos.

Answer 1

"Find the area of the triangle"

Answer 2

Forgot to add that in there

Answer 3

It's not equilateral as the sides are not congruent. We know that \[A = \frac{ 1 }{ 2 }bh\] but this is for a right angle triangle so using this as a reference to draw a new picture

Answer 4

so for a non right angle triangle we can use the area \[A = \frac{ 1 }{ 2 }absinC\]