oy is giving ice cream cones to some children at a carnival. She has 8 chocolate ice cream cones, 10 vanilla ice cream cones, and 6 strawberry ice cream cones. If Joy selects an ice cream cone randomly without looking, what is the probability that she will give a chocolate ice cream cone to the first child and then a vanilla ice cream cone to the second child?
8 over 24 plus 10 over 24 is equal to 18 over 24
8 over 24 plus 10 over 23 is equal to 424 over 552
8 over 24 multiplied by 10 over 23 is equal to 80 over 552
8 over 24 multiplied by 10 over 24 is equal to 80 over 576
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OpenStudy (moazzam07):
@heretohelpalways
OpenStudy (anonymous):
i am here
OpenStudy (moazzam07):
You are the best
OpenStudy (anonymous):
add all the ice cream cones up
OpenStudy (anonymous):
lol thanks
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OpenStudy (moazzam07):
24
OpenStudy (anonymous):
which is 24
OpenStudy (moazzam07):
ok
OpenStudy (anonymous):
so there will be 8 over 24 for the chocolate ice cream cones
OpenStudy (moazzam07):
Correct
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OpenStudy (anonymous):
and since one cone was taken out, the denominator for the next fraction probability would be 23
OpenStudy (anonymous):
and there are 10 vanilla ice cream cones
OpenStudy (anonymous):
so 10/23
OpenStudy (anonymous):
so 8 over 24 * 10 over 23
OpenStudy (moazzam07):
So its not A and D
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