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If cos x = .75, what is sin x? 0.87 0.75 0.66 0.69
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okay so you have to solve for x and then plug that value into the sin(x) function
looks like they want the answer to be positive. sin(x) = sqrt(1 - cos^2(x))
do sqrt(1 - (0.75)^2)
so it would be 0.66?
or would you round?
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actually i think its just a simple arccos question \[\cos(x) = .75\] \[x = \cos^-1(.75)\] and then plug that value into sin(x)
ohhh ok thanks
but either way you get the same answer .661
Thanks alot!
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