Question

Solving for x: (x^2- a^2)= 3(x+a)

Answer 1

\[x^2-a^2-3\left( x+a \right)=0\]
\[\left( x+a \right)\left( x-a \right)-3\left( x+a \right)=0\]
\[\left( x+a \right)\left( x-a-3 \right)=0\]
equate each factor to 0 and find x

Answer 2

How do you get from (x+a)(x-a)-3(x+a)=0 to (x+a)(x-a-3)=0 ??

Answer 3

\[a^2-b^2=\left( a+b \right)\left( a-b \right)\]
i have taken x+a common from both factors.