Question

Simplify completely quantity 2 x squared plus 20 x plus 32 all over x squared minus 2 x minus 80.

Answer 1

A negative 1 over 5
B negative 2 over 5
C 5 x over quantity x minus 5
D 2 open parentheses x plus 2 close parentheses over x minus 10

Answer 2

\[\frac{2 x^2+20x+32 }{ x^2-2x-80 }\]
\[=\frac{ 2\left( x^2+10x+16 \right) }{ x^2-2x-80 }\]
10=8+2
8*2=16
10-8=2
10*-8=-80
make factors and cancel common factor