Question

Find the roots of the function f(x)=(x-8)^2-1

Answer 1

What do you think?

Answer 2

i have no clue honestly

Answer 3

to find the root set the function = 0 and solve for x

Answer 4

\[(x-8)^{2}-1 = x^2-16x+64-1=x^{2}-16x+63 = 0\]

Answer 5

ok so i would do (x-8)^2-1=0?

Answer 6

Follow ginochen

Answer 7

Solve for

\( \large x^{2}-16x+63 = 0\)