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How does sin* 1/cos give tan sec
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I know 1/cos is sec but where does tan come from?
never mind its cos^2
\[\tan = \frac{ 1 }{ \color{reD}{\cot} }\] cot = cos /sin so \[\tan = \frac{ 1 }{ \color{reD}{\frac{ \cos }{ \sin }} }\] multiply 1 with the reciprocal of the bottom fraction \[\tan =\frac{ \sin }{ \cos }\] lolol
ohh okay I was like what type of question is this :P lol
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