Question

Solve for x: the quantity of x plus 20 over 2 = 3x

x = 10
x = 4
x = −14
x = −17

Answer 1

\[\frac{ (x+20) }{ 2 }=3x\]\[(2)\frac{ (x+20) }{ 2 }=3x(2)\]\[(x+20)=6x\]\[20=6x-x\]\[20=5x\]\[\frac{ 20 }{ 5 }=x\]\[4=x\]

Answer 2

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