What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1?

f(x) = −one fourth (x − 5)2 + 1
f(x) = one fourth (x − 5)2 + 1
f(x) = −one fourth (x − 5)2
f(x) = one fourth (x − 5)2

Question

What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1?

f(x) = −one fourth (x − 5)2 + 1
f(x) = one fourth (x − 5)2 + 1
f(x) = −one fourth (x − 5)2
f(x) = one fourth (x − 5)2

freckles · Answer

i like to draw first...
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the vertex will be halfway between the directrix and the focus

freckles · Answer

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what are the coordinates for V