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Find the between graphs of y=x^2+2 and y=1-x between x=0 and x=1. Can you guys please check if my equation is right, I will type it below.
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Find what?
Area ?
Find the area oops
Makes sense
[(1-x)-(x^2+2)]
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limits 0 to 1
backwards
parabola is above the line, not below it
ooopsss I think my drawing is wrong
which line?
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|dw:1438743560886:dw| i thought this is like this
not if it is \(y=x^2+2\)
upper strip - lower strip right?
You had y=x^2+2, the parabola is shifted up to 2 units Yes, i graphed mines a little off |dw:1438743695117:dw|
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