Question

how do you factor
3x³-7x²-7+3x
help

Answer 1

did you get anywhere yet?

Answer 2

Try rearranging...

\[3x^3 + 3x - 7x^2-7\]

Answer 3

factor the first 2 terms, and the last 2 terms...

Answer 4

\[3x*(x^2+1) + (-7)*(x^2+1)\]

Answer 5

now just factor a (x^2+1) from both terms

Answer 6

\[(x^2+1)(3x-7)\]

Answer 7

you see?

Answer 8

yes thank you
very much

Answer 9

welcome

Answer 10

(x2+1)(3x−7)