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Triangle ABC is congruent to triangle XYZ. Angle A measures 50 degrees angle B measure (2x+40) degrees and angle X measures (4x+8) degrees Find the value of x. I got 13.67
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Hey Kate :) Since A is the first angle in triangle ABC, and X is the first angle in triangle XYZ, and given that the triangles are `congruent`, this tells us that angle A is equivalent to angle X. Therefore \(\large\rm 50=4x+8\) Solve for x! :) I don't think it quite works out to 13.67.
14.5?
Subtract 8,|dw:1438786120187:dw|
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