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Solve 3x2 + 18x + 15 = 0 by completing the square. 3(x + 3)2 = 6; x = −3 + square root 2, x = −3 − square root 2 3(x + 9)2 = 12; x = −11, x = −7 3(x + 3)2 = 12; x = −5, x = −1 3(x + 9)2 = 228; x = −9 + square root 76, x = −9 − square root 76
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divide by 3
\[x^2+6x+5=0\] \[x^2+6x=-5\] add both sides \[\left( \frac{ 6 }{ 2 } \right)^2 ~i.e.,9\] \[x^2+6x+9=-5+9\] \[\left( x+3 \right)^2=2^2\] \[x+3=\pm2,x=?\]
4?
no
x+3=2 x=?
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-1
correct and x+3=-2 x=?
-5
correct these are two values of x
THANK YOUUUU :)
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