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Mathematics 7 Online
OpenStudy (anonymous):

Can someone help me?

OpenStudy (anonymous):

An expression is shown below: 3(m + 5 + 9m) Part A: Write two expressions that are equivalent to the given expression. Part B: Show that one of your expressions in Part A is equivalent to the given expression using algebraic properties. Explain which properties you used. Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m.

OpenStudy (mertsj):

What test is this?

OpenStudy (anonymous):

its not a test

OpenStudy (mertsj):

For the first part, distribute the 3. That gives you one equivalent expression.

OpenStudy (mertsj):

To get a second equivalent expression, add m+9m. That gives you a second equivalent expression.

OpenStudy (anonymous):

what do you mean by distribute?

OpenStudy (mertsj):

3(x+4)=3x+12

OpenStudy (mertsj):

I distributed the 3

OpenStudy (anonymous):

15+30m

OpenStudy (anonymous):

@Mertsj

OpenStudy (mertsj):

3(m+5+9m)=3m+15+27m You don't have to combine the like terms according to the directions.

OpenStudy (anonymous):

ok

OpenStudy (mertsj):

For the second part, explain that you used the distributive property like this: 3(m+5+9m)=3(m)+3(5)+3(9m)

OpenStudy (mertsj):

For the third part pick a number like 2 and use the original expression and your other expression from part 2 and replace m with 2 in both expressions and show that you get the same answer for both.

OpenStudy (anonymous):

@Mertsj so my two equivalent expressions are 15+30m and 3m+15+27m

OpenStudy (mertsj):

When you distribute the 3 you get 3m+15+27m That's one of the equivalent expressions.

OpenStudy (mertsj):

When you add m +9m you get 3(5+10m) That's the other equivalent expression

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

BTW~ thank you so much @Mertsj

OpenStudy (mertsj):

yw

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