Question

Solve the following system of equations:

y = x2 + 3
y = x + 5

Please i just want someone to walk me through the steps of substitution?

Answer 1

put
\[x^2+3=x+5\] and solve the quadratic equation

Answer 2

I tried that and I know my answer is wrong because it doesn't make any sense

Answer 3

x=-1,x=2

Answer 4

y=x+5 so put this value of y in the second equation,y=x^2+3
x+5=x^2+3
x^2-x-2=0
now middle term breaking
x^2-2x+x-2=0
now take x common from the first part

Answer 5

and 1 from the second part
so it is ,x(x-2)+1(x-2)=0
(x-2)(x+1)=0
x=2or x=-1

Answer 6

Thank you so much!!