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A rectangular parking lot has a length that is 15 yards greater than the width. The area of the parking lot is 450 square yards. Find the length and the width. Use the formula, are = length * width.
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15 yards greater than the width = x(x+15) Is that to what it translates to?
Let Width = W and Length = W + 15 |dw:1438833371504:dw| If the area in total = 450 We have \[\large Length \times Width = 450\] \[\large (W+15) \times W = 450\] Solve for 'w' and then solve for 'l'
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