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what is the length(magnitude) of the vector (6,-3)? A. 3sqrt2 B. sqrt2 C. 3 D. sqrt53
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length of vector \((a,b)\) is \(\sqrt{a^2+b^2}\)
You need the hypotenuse of the right triangle. |dw:1438838359010:dw|
would I be using the Pythagorean theorem?
√(6^2 + (-3)^2) = √(36+9) = √(9*5) = 3√5
Yes, Pythagoras' Theorem is the way to figure out the length of this vector.
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