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Which expression is equivalent to sin2x−sinx−2/sinx−2 ? sin x + 1 sin x − 1 sin2x -sin2x
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I'm a bit confused... for the sin2x part is it really sin2x or (sinx)^2 -> sin^2x
\[\large \frac{\sin^2x-sinx-2}{sinx-2} \] like this?
yes sorry
i get a decimal but there isn't decimals
yeah that would work... it's just like factoring only with trigs attached to it \[\large \frac{(sinx-2)(sinx+1)}{sinx-2}\] cancel like terms and see what happens
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sinx+1
:) yes
oh wow i was so over thinking that lol thank you so much for your help
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