@Michele_Laino
A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?
1/4096
1/512
1/64
1/8

Question

@Michele_Laino
A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?
1/4096
1/512 
1/64 
1/8

michele_laino · Answer

Hint:
the requested probabilitiy is the product of  the single three probabilities

anonymous · Answer

$$\left(\frac{1}{8}\right)^3=\frac{1}{512} $$

anonymous · Answer

ohhhh

michele_laino · Answer

since each of the three probability is equal to 1/8