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Derive the equation of the parabola with a focus at (4, −7) and a directrix of y = −15. Put the equation in standard form.
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ok... have you plotted the information on the number plane so you know the concavity of the parabola..?
yeah
So, you can still use the combined distance equation for this problem. But you just have to make your solution ax^2+bx+c=0.
ax+by=c.
so is the directrix above or below the focus...? and then is the parabola concave up or down..?
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|dw:1438892282167:dw| so you plot looks like this
below right?
|dw:1438892378795:dw| the distance is labelled 2a and is double the focal length.
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