Question

Belinda wants to invest $1000. The table below shows the value of her investment under two different options for three different years:


Number of years 1 2 3
Option 1 (amount in dollars) 1300 1690 2197
Option 2 (amount in dollars) 1300 1600 1900


Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points)

Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points)

Part C: Beli

Answer 1

Part C: Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1? Explain your answer, and show the investment value after 20 years for each option. (4 points)

Answer 2

I ONLY NEED PART C IGIVE MEDALS :)

Answer 3

@Luigi0210

Answer 4

@mathmate

Answer 5

@Nnesha

Answer 6

@sammixboo

Answer 7

@DanJS

Answer 8

@Kainui

Answer 9

help please?

Answer 10

20 year value,

n = 20, put that in both of your functions from part B

Answer 11

can you show me how to solve it

Answer 12

what are your functions from part b ?

Answer 13

1300+300n
1300+300n* 1.3n

Answer 14

hmm
The first option is exponential form (1000)*(r)^n
The second option is linear form 1000 + n*d

have to figure what r and d are

Answer 15

Option 1) THe function looks like (initial investment)*(r)^n
\[f(n) = 1000*(r)^n\]

r is the common ratio of consecutive terms

1300/1000 = 1.3 or 1690/1300 = 1.3 or 2197/1690 = 1.3

r is 1.3

Answer 16

f(n) = 1000(1.3)^n

Answer 17

Each next term is the previous multiplied by 1.3

Answer 18

Option 2) Each term increases by the same amount over the previous term, it is always 300 more

Answer 19

f(n) = (starting value) + n*(common difference)

f(n) = 1000 + 300*n

Answer 20

so i use this to solve for the difference
right?

Answer 21

1) f(n) = 1000(1.3)^n

2) f(n) = 1000 + 300*n

yep, put n=20 in both options and calculate the values

Answer 22

do i subtract both of the answers i get for the answer

Answer 23

you dont have to, just compare them

Answer 24

option 1 should be way larger

Answer 25

yes it was that you so much :)

Answer 26

*thank

Answer 27

welcome