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The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t2 - 0.5t + 3.5 The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year. Numerical Answers Expected!
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1.5 right?
lmLtfy!! \(\large f(t) = 0.25t^2 - 0.5t + 3.5\) so \(\huge \frac{f(6) - f(2)}{6 - 2} = ????\) then, remembering that they want the answer in " **thousand** owners per year ", be sure to divide by 1,000.
is it 1.5?
@Nnesha is it 1.5? YES OR NO?????????????
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