Match the verbal expression (term) with its algebraic expression (definition).
Match Term Definition
A variable cubed A) y − 3
Quotient of some number and three B) 3a
Product of an unknown value and three C) z + 3
Three less than a variable D) x3
Three more than some number E) b ÷ 3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i will fan and medal
OpenStudy (astrophysics):
A variable cubed, what do you think that?
OpenStudy (astrophysics):
What does it mean when something is cubed
OpenStudy (anonymous):
raised to the third power
OpenStudy (astrophysics):
Exactly! And a variable can be anything, x, y, z..etc
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (astrophysics):
Which one will be then?
OpenStudy (anonymous):
ok so a variable cubed is x*3
OpenStudy (astrophysics):
Yes \[x^3\]
OpenStudy (astrophysics):
Ok next one, `Quotient of some number and three`what is a quotient?
OpenStudy (anonymous):
the result of dividing
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (astrophysics):
Exactly! Quotient = division you know this stuff :) so which will it be
OpenStudy (anonymous):
b divided by 3
OpenStudy (astrophysics):
good :)
OpenStudy (astrophysics):
Ok so `Product of an unknown value and three` how about this one, what is a product
OpenStudy (anonymous):
the result of multiplying
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (astrophysics):
Right! And the answer for that is?
OpenStudy (anonymous):
3a
OpenStudy (astrophysics):
Nice!
Ok now this one `Three less than a variable` which one do you think it is
OpenStudy (anonymous):
y-3
OpenStudy (astrophysics):
Good, and the final one, three more than a number is?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
z+3 thank you can you help me with 2 more
OpenStudy (astrophysics):
Your welcome, and I can try, please open another question :)