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8 equals the square root of 3x solve for x
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\(8 = \sqrt{3x}\) or \(8 = \sqrt{3}x\)
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\[8=\sqrt{3x}\] This is when you work backwords. To get rid of the square root you have to square it, and you will be squaring the 8 as well. \[8^{2} = (\sqrt{3x})^{2}\] and it leaves you with: \[64=3x\] Divide three on both sides: \[64/3 = 3x/3\] \[64/3 = x\]
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