Question

Any help?

Answer 1

On this

Answer 2

Here I will do something similar

\((\dfrac{a^3b^3}{a^2b^7})^2=\dfrac{(a^3b^3)^2}{(a^2b^7)^2}=\dfrac{(a^3)^2(b^3)^2}{(a^2)^2(b^7)^2}=\dfrac{a^6b^6}{a^4b^{14}}=a^{6-4}b^{6-14}=a^2b^{-12}=\dfrac{a^2}{b^{12}}\)