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Simplify. (–12x) ÷ (–2) A.12x B.1/12x C.3x D.6x
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hint: we have this: \[\Large \frac{{ - 12x}}{{ - 2}} = \left( {\frac{{ - 12}}{{ - 2}}} \right)x = ...?\]
D
correct!
YEAHHHH THANKS :D . @Michele_Laino
:)
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