Please check if this is right???
A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function r(t) = 3t, where t represents time in minutes and r represents how far the paint is spreading. The flowing paint is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2. Part A: Find the area of the circle of spilled paint as a function of time, or A[r(t)]. Show your work. Part B: How large is the area of spilled paint after 10 minutes? You may use 3.14 to approximate π in this problem.
Part A: You will plug in 3t to A(r) = pir^2 When you plug in the 3t you get: A[r(t)]= pi(3t)^2 =pi * (3t)^2 =pi * (3t * 3t) =28.274334t^2 ( I was just simplifying). Part B: 30 is r, because 30 is the radius after 10 minutes: π(30)2=900π = 900 x 3.14=2826
@hartnn @Elsa123
part A, don't simplify, write \(9\pi t^2\) as the answer. part B, writing units would be better 2826 sq. units
it also says show your work for part a so what would i put and ok for part b
you did show your work for part A properly, just keep the final answer as 9pi t^2 and instead of writing answer for part B as 2826 write 2826 sq. units
Part B: 10 is r, because 10 is the radius after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 sq units. ^^^
yes i saw :)
wait
I'm here :)
Part B: 10 is t, because we need area after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 sq units. ------------------ t =10, 10 is actually time :P
Is this what you would like me to do with Part A? : Part A: You will plug in 3t to A(r) = pir^2 When you plug in the 3t you get: A[r(t)]= pi(3t)^2 =pi * (3t)^2 =pi * (3t * 3t) =9pit^2
yep
ok so is 30 still radius or ?
(just out of curiosity)
where did you get 30 from?? i don't even see 30 in the question :P
but yes, 30 will be the radius after 10 minutes :)
yes
I believe i multiplied 10 x 3 in 3(t) to get 30 and called it radius. To think about it that was stupid.
@hartnn r(t) = 3t and 10 = 10 so r = 30
yes, i agreed, r =30
Is this what you wanted me to do with part a: Part A: You will plug in 3t to A(r) = pir^2 When you plug in the 3t you get: A[r(t)]= pi(3t)^2 =pi * (3t)^2 =pi * (3t * 3t) =9pit^2
yes, part A is perfect
wait so what about pt b?
Part B: 10 is t, because we need area after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 So, the answer is 2826 sq. units.
Part B: 10 is t, because we need area after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 sq units. yesss
ok so everything is bueno?
bueno? yes, everything is okay :)
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